Mr.Math
  • Mr.Math
Find the sum \(\large \sum_{k=1}^{n} k!(k^2+k+1).\)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
\( \large \sum \limits_{k=1}^{n} k!(k^2+k+1) = (n+1)!(n+1)-1 \) PS: Latex Tip included ;-)
Mr.Math
  • Mr.Math
You should show work, so others can learn :-)
Zarkon
  • Zarkon
\[k^2+k+1=(k+1)^2-k\]

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More answers

Zarkon
  • Zarkon
is my hint good enough?
Mr.Math
  • Mr.Math
Yes.
anonymous
  • anonymous
One more hint, \( \large \sum \limits_{k=1}^{n} k\times k! = (n+1)! -1\)
anonymous
  • anonymous
oops MR.Math is great :)
Mr.Math
  • Mr.Math
lol, I already know the answer. I just wanted to post something, and I think it's a nice problem.
anonymous
  • anonymous
haha :)
anonymous
  • anonymous

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