Mr.Math
Find the sum \(\large \sum_{k=1}^{n} k!(k^2+k+1).\)



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FoolForMath
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\( \large \sum \limits_{k=1}^{n} k!(k^2+k+1) = (n+1)!(n+1)1 \)
PS: Latex Tip included ;)

Mr.Math
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You should show work, so others can learn :)

Zarkon
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\[k^2+k+1=(k+1)^2k\]

Zarkon
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is my hint good enough?

Mr.Math
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Yes.

FoolForMath
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One more hint, \( \large \sum \limits_{k=1}^{n} k\times k! = (n+1)! 1\)

FoolForMath
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oops MR.Math is great :)

Mr.Math
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lol, I already know the answer. I just wanted to post something, and I think it's a nice problem.

FoolForMath
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haha :)
