## anonymous 4 years ago what is (2 sq. root of 6z+1) ^2 ? My brain is dead! I would actually write it out if I could, but I don't know how to do that on here

1. anonymous

sqrt(6z+1)^2 =6z+1

2. amistre64

$\sqrt{(a*a)}=a$ $(\sqrt{a})(\sqrt{a})=a$

3. anonymous

thank you!

4. anonymous

my pleasure good luck bye