x^2+y^3+4y=4 ,what is the equation of the tangent to the curve of the above equation at -1,1

x^2+y^3+4y=4 ,what is the equation of the tangent to the curve of the above equation at -1,1

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implicit derivation:
2x + 3(y^2)(y') + 4(y') = 0
y' = (-2x) / (3y^2 + 4)
replace: y'(-1, 1) = 2/7

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