A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.4there are 3 squares next to each other. prove C = A + B

Mr.Math
 2 years ago
Best ResponseYou've already chosen the best response.13 squares with the same side length I presume?

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.4yes  3 identical squares

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.4BTW: This is a geometry challenge  so no trig allowed :)

FoolForMath
 2 years ago
Best ResponseYou've already chosen the best response.1Okay I can solve it using height and distance, one interesting fact: \( \sin(CB) = \sin (C) \sin (B) \)

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.4:D  think "outside" the box

FoolForMath
 2 years ago
Best ResponseYou've already chosen the best response.1Comone why not use trig? :P

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.4ok  lets see the trig solution. but there is a very elegant geometric solution if you can find it. :)

FoolForMath
 2 years ago
Best ResponseYou've already chosen the best response.1Hmm Asnaseer rules :D

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.4I'm off to have some food  will be back soon ...

Mr.Math
 2 years ago
Best ResponseYou've already chosen the best response.1I can't seem to be able to find a geometrical proof. Here's a proof using trigonometry: We have \(\sin C=\frac{1}{\sqrt{2}}\), \(\sin B=\frac{1}{\sqrt{5}}\), \(\sin A=\frac{1}{\sqrt{10}}\), and \(\cos A=\frac{3}{\sqrt{10}}\), \(\cos B=\frac{2}{\sqrt{5}}.\) It's easy to show that \(\sin C=\sin(A+B)\) and hence \(C=A+B \text{ because } A,B, C \in (0, \frac{\pi}{2}).\)

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.4I'll let this problem /simmer/ for a while before showing the geometric proof  unless of course someone actually proves it by then :)

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.4I gave a hint above  think "outside" the box :)

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.4I guess I can give another hint to you guys, here it is...

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.4dw:1328468434372:dw essentially, you want to try and prove that D=B

Shayaan_Mustafa
 2 years ago
Best ResponseYou've already chosen the best response.0It can be proof using Euclidean concepts of geometry i.e. using theorems, postulates, axiom etc... It is actually difficult. But intresting.

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.4There is actually a much easier proof using only the properties of similar triangles.

Shayaan_Mustafa
 2 years ago
Best ResponseYou've already chosen the best response.0Yes I know in terms of Euclidean Geometry. These properties of triangles are followed by, called, postulates.
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.