asnaseer
  • asnaseer
Geometry challenge. Question to follow in drawing.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
asnaseer
  • asnaseer
|dw:1328465419159:dw|
asnaseer
  • asnaseer
there are 3 squares next to each other. prove C = A + B
Mr.Math
  • Mr.Math
3 squares with the same side length I presume?

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asnaseer
  • asnaseer
yes - 3 identical squares
asnaseer
  • asnaseer
BTW: This is a geometry challenge - so no trig allowed :)
anonymous
  • anonymous
Okay I can solve it using height and distance, one interesting fact: \( \sin(C-B) = \sin (C) \sin (B) \)
anonymous
  • anonymous
Snap! asnaseer :P
Mr.Math
  • Mr.Math
Oh man, this sucks!
asnaseer
  • asnaseer
:D - think "outside" the box
anonymous
  • anonymous
Comone why not use trig? :P
asnaseer
  • asnaseer
ok - lets see the trig solution. but there is a very elegant geometric solution if you can find it. :)
anonymous
  • anonymous
Hmm Asnaseer rules :D
asnaseer
  • asnaseer
I'm off to have some food - will be back soon ...
Mr.Math
  • Mr.Math
I can't seem to be able to find a geometrical proof. Here's a proof using trigonometry: We have \(\sin C=\frac{1}{\sqrt{2}}\), \(\sin B=\frac{1}{\sqrt{5}}\), \(\sin A=\frac{1}{\sqrt{10}}\), and \(\cos A=\frac{3}{\sqrt{10}}\), \(\cos B=\frac{2}{\sqrt{5}}.\) It's easy to show that \(\sin C=\sin(A+B)\) and hence \(C=A+B \text{ because } A,B, C \in (0, \frac{\pi}{2}).\)
asnaseer
  • asnaseer
I'll let this problem /simmer/ for a while before showing the geometric proof - unless of course someone actually proves it by then :)
anonymous
  • anonymous
any hints?
asnaseer
  • asnaseer
I gave a hint above - think "outside" the box :)
asnaseer
  • asnaseer
I guess I can give another hint to you guys, here it is...
asnaseer
  • asnaseer
|dw:1328468434372:dw| essentially, you want to try and prove that D=B
Shayaan_Mustafa
  • Shayaan_Mustafa
It can be proof using Euclidean concepts of geometry i.e. using theorems, postulates, axiom etc... It is actually difficult. But intresting.
asnaseer
  • asnaseer
There is actually a much easier proof using only the properties of similar triangles.
Shayaan_Mustafa
  • Shayaan_Mustafa
Yes I know in terms of Euclidean Geometry. These properties of triangles are followed by, called, postulates.

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