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Please find my problem attached.

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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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  • phi
Do you know trigonometry. If so, find the altitude h of the triangle using sin(72º)= h/6 your figure is a parallelogram (that is what those >> marks tell you), so the top side equals the bottom side. So AB has length 12. AE has length AB/3 = 4 the area of the parallelogram is h*base = h*12 (h from above) the area of the triangle is (1/2)*h*AE= (1/2)*h*4= 2*h (h from above) area of the shaded area = h*12 - 2*h = 10*h so find h!
i got 60cm^2

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  • phi
how?
12*6 =area of the parallelogram 4*6*1/2= area of triangle and I subtracted the triangle from the parallelogram
  • phi
pretty close. Except 6 is not the height of the parallelogram. you need the height |dw:1328468550292:dw|
how to I find that?
  • phi
trigonometry. the sine of an angle is opposite over hypotenuse |dw:1328468701639:dw|
1 Attachment
sorry you looking for 5S..
i dont know any trig
just use calculater..
  • phi
looks like you need to learn it
42.8=shaded area
  • phi
@cinar, are you sure?
sorry guys
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57.06=shaded area
  • phi
If you want to learn, here are two short videos that might help http://www.khanacademy.org/video/basic-trigonometry?topic=trigonometry he has more, if you like them

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