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anonymous
 4 years ago
integral of xcos4x with explanation please?
anonymous
 4 years ago
integral of xcos4x with explanation please?

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myininaya
 4 years ago
Best ResponseYou've already chosen the best response.5\[\int\limits_{}^{}x \sin(4x) dx=x \cdot \frac{1}{4} \cos(4x)\int\limits_{}^{}\frac{1}{4} \cos(4x) dx\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Is there any calculus problem that myin can't solve?

EarthCitizen
 4 years ago
Best ResponseYou've already chosen the best response.0are u sure it's not 4x^2

EarthCitizen
 4 years ago
Best ResponseYou've already chosen the best response.0myin, it's an indefinite integral

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[1/4*\sin 4x *x +1/16*\cos 4x \]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.5i know it is an indefinite integral integration by parts is the way to do this one the way i showed above

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{}^{}x \sin 4xdx\]\[u = x, du = dx\]\[dv = sen(4x)dx\]\[v = (1/4)\cos (4x)\]\[\int\limits_{}^{}udv = uv  \int\limits_{}^{}vdu\]\[\int\limits_{}^{}x \sin 4xdx = x(1/4)\cos 4x  \int\limits_{}^{}(1/4)\cos(4x)dx\]= x(1/4)cos 4x  (1/4)((1/4)sen(4x)) =x(1/4)cos 4x + (1/16)sen(4x)
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