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anonymous
 4 years ago
how many possible combinations can there be with the numbers 6,6,4,4,1?
anonymous
 4 years ago
how many possible combinations can there be with the numbers 6,6,4,4,1?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if they were all different you would have 6! combinations, but since you cannot tell the 6s apart, nor the twos, it is \[\frac{6!}{2\times2}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0"6,6,4,4,1" are 5 numbers isn't ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah i guess it is isn't it!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so if it was 42333 what would it be? whats the general formula?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what is an additional number between friends? ok i was wrong, maybe try \[\frac{5!}{2\times 2}\] if you want to actaully get the correct answer

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\frac{5\times 4\times 3\times 2}{2\times 2}=5\times 3\times 2=30\] (did i get that right?)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0looks correct, but what is the general formula?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\frac{5!}{3!}\] for the second one

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so that otheer one is really 2!x2! in the denominator?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes, if you want to think of it that way. the number of ways you can permute 2 things is 2! = 2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0awesome thanks so much!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sorry about miscounting

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0its all good... all worked out!
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