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anonymous

  • 4 years ago

how many possible combinations can there be with the numbers 6,6,4,4,1?

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  1. anonymous
    • 4 years ago
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    if they were all different you would have 6! combinations, but since you cannot tell the 6s apart, nor the twos, it is \[\frac{6!}{2\times2}\]

  2. anonymous
    • 4 years ago
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    "6,6,4,4,1" are 5 numbers isn't ?

  3. anonymous
    • 4 years ago
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    lol

  4. anonymous
    • 4 years ago
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    yeah i guess it is isn't it!

  5. anonymous
    • 4 years ago
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    so if it was 42333 what would it be? whats the general formula?

  6. anonymous
    • 4 years ago
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    what is an additional number between friends? ok i was wrong, maybe try \[\frac{5!}{2\times 2}\] if you want to actaully get the correct answer

  7. anonymous
    • 4 years ago
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    haha :D

  8. anonymous
    • 4 years ago
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    \[\frac{5\times 4\times 3\times 2}{2\times 2}=5\times 3\times 2=30\] (did i get that right?)

  9. anonymous
    • 4 years ago
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    looks correct, but what is the general formula?

  10. anonymous
    • 4 years ago
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    \[\frac{5!}{3!}\] for the second one

  11. anonymous
    • 4 years ago
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    so that otheer one is really 2!x2! in the denominator?

  12. anonymous
    • 4 years ago
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    yes, if you want to think of it that way. the number of ways you can permute 2 things is 2! = 2

  13. anonymous
    • 4 years ago
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    awesome thanks so much!

  14. anonymous
    • 4 years ago
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    yw

  15. anonymous
    • 4 years ago
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    sorry about mis-counting

  16. anonymous
    • 4 years ago
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    its all good... all worked out!

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