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  1. Hero
    • 4 years ago
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    |dw:1328468993493:dw|

  2. Lukecrayonz
    • 4 years ago
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    Hero, this is my teachers explanation "28] Here draw the plane to the top right and connect the lines as explained in the problem. You will see that the long side of your left triangle is equal to the hypotenuse of your triangle that is on the right. the altitude is the distance from the plane to the ground which is a side of your triangle on the right. First use Law of sines to find the long side of your triangle on the left and then use the fact that sine is opposite over hypotenuse to find your opposite side.". I am honestly, completely lost. Can you please help a little bit more?

  3. anonymous
    • 4 years ago
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    |dw:1328470459577:dw|

  4. anonymous
    • 4 years ago
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    there is my lousy picture

  5. Lukecrayonz
    • 4 years ago
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    Well those are largely different D:

  6. anonymous
    • 4 years ago
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    the triangle on the left has two angles you know 51 and 180-68 = 112 so you can find the third angle as 180 - 112 - 51 = 17 and one side that you know 2.5 so presumably we can solve the triangle using the laws of sines

  7. Lukecrayonz
    • 4 years ago
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    And the exact equation of that would be..

  8. anonymous
    • 4 years ago
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    |dw:1328470818902:dw|

  9. Lukecrayonz
    • 4 years ago
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    |dw:1328470842566:dw| See I had that and I confused myself more because obviously you cant have a zero angle.

  10. anonymous
    • 4 years ago
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    i suck a drawing these, but you should have \[\frac{x}{\sin(51)}=\frac{2.5}{\sin(17)}\]

  11. anonymous
    • 4 years ago
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    that picture is not right. you want a right triangle, not those

  12. Lukecrayonz
    • 4 years ago
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    Or is the angle 68 just me pulling something out of my retrice

  13. anonymous
    • 4 years ago
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    |dw:1328470950021:dw|

  14. anonymous
    • 4 years ago
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    i cannot draw here, but this is what i think you should be looking at.

  15. Lukecrayonz
    • 4 years ago
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    Well I'm nearly 100% sure I did that wrong because I got 6.6 :S

  16. anonymous
    • 4 years ago
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    so as i said, \[\frac{x}{\sin(51)}=\frac{2.5}{\sin(17)}\] and therefore \[x=\frac{2.5\sin(51)}{\sin(17)}\] \[x=6.65\] rounded. now we need the altitude

  17. anonymous
    • 4 years ago
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    we now look at this triangle |dw:1328471113714:dw|

  18. Lukecrayonz
    • 4 years ago
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    I got 6.1

  19. anonymous
    • 4 years ago
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    and we see that \[\frac{A}{6.65}=\sin(68)\] so \[A=6.65\sin(68)=6.166\] rounded

  20. anonymous
    • 4 years ago
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    looks good, depending on how you round

  21. Lukecrayonz
    • 4 years ago
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    Thank you so much :D

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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