A community for students.
Here's the question you clicked on:
 0 viewing

This Question is Closed

sasogeek
 4 years ago
Best ResponseYou've already chosen the best response.3use the cosine rule, u have the required lengths, the only thing missing is the angle, plug in the values into the equation and solve for \(\theta\)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what saso said. law 'o cosines for this one

Lukecrayonz
 4 years ago
Best ResponseYou've already chosen the best response.0a^2=b^2+c^22(b)(c)cosA

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes but of course you want \[\theta\] not a length

Lukecrayonz
 4 years ago
Best ResponseYou've already chosen the best response.09=2^2+3^22(2)(3)cosX

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what you are looking for is the angle right? so you need to use \[\theta=\cos^{1}(\frac{b^2+c^2a^2}{2bc})\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0or you could use what you wrote above to solve for \[\cos(\theta)\] and then take the inverse cosine to get theta. amounts to the same thing

sasogeek
 4 years ago
Best ResponseYou've already chosen the best response.3\(a=4\frac{1}{2} \ \ b=2 \ \ \ c=3\)

Lukecrayonz
 4 years ago
Best ResponseYou've already chosen the best response.0One last question! Woohoo!

sasogeek
 4 years ago
Best ResponseYou've already chosen the best response.3looking at the picture, u can simply tell that the angle is greater than 90... 70.5 is definitely not the right answer
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.