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anonymous

  • 4 years ago

I need help...I don't understand or know what to do or where to start. F(x)=-2(x^2-4)/3(x^2+4x+4)

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  1. jhonyy9
    • 4 years ago
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    2(x-2)(x+2) ----------- = 2(x-2)/(3(x+2)) 3(x+2)^2 - hope so much that is understandably sure

  2. jhonyy9
    • 4 years ago
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    good luck bye

  3. jhonyy9
    • 4 years ago
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    ok ?

  4. anonymous
    • 4 years ago
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    so it is just pretty much like an elimination thing

  5. jhonyy9
    • 4 years ago
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    yes right

  6. anonymous
    • 4 years ago
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    so do i try to solve the final equation or no

  7. jhonyy9
    • 4 years ago
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    x^2 -4 =(x-2)(x+2) --- us formula a^2 -b^2 =(a-b)(a+b) x^2 +4x +4 =(x+2)^2

  8. jhonyy9
    • 4 years ago
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    you need to solve it again ?

  9. anonymous
    • 4 years ago
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    so on the 1st 1 would it be 0--x cancels and 2 cancels

  10. jhonyy9
    • 4 years ago
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    so sorry i have missed yes there is -2(x-2)/(3(x+2))

  11. anonymous
    • 4 years ago
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    im not understanding what you were saying there in your last response

  12. jhonyy9
    • 4 years ago
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    before i have wrote there in numerator 2(x-2/ i now i have said that there is -2

  13. jhonyy9
    • 4 years ago
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    so you need to solve it ?

  14. jhonyy9
    • 4 years ago
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    than you need to suppose that x not can being -2 because than the denominator will be equal zero and than the fraction is undefined

  15. jhonyy9
    • 4 years ago
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    but x=2 is right

  16. jhonyy9
    • 4 years ago
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    like solution of it

  17. anonymous
    • 4 years ago
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    yes i do understand now thank you

  18. anonymous
    • 4 years ago
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    http://www.wolframalpha.com/input/?i=%28-2%28x%5E2-4%29%29%2F%283%28x%5E2%2B4x%2B4%29%29

  19. jhonyy9
    • 4 years ago
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    yw my pleasure good luck bye

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