I need help...I don't understand or know what to do or where to start. F(x)=-2(x^2-4)/3(x^2+4x+4)

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I need help...I don't understand or know what to do or where to start. F(x)=-2(x^2-4)/3(x^2+4x+4)

Mathematics
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2(x-2)(x+2) ----------- = 2(x-2)/(3(x+2)) 3(x+2)^2 - hope so much that is understandably sure
good luck bye
ok ?

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Other answers:

so it is just pretty much like an elimination thing
yes right
so do i try to solve the final equation or no
x^2 -4 =(x-2)(x+2) --- us formula a^2 -b^2 =(a-b)(a+b) x^2 +4x +4 =(x+2)^2
you need to solve it again ?
so on the 1st 1 would it be 0--x cancels and 2 cancels
so sorry i have missed yes there is -2(x-2)/(3(x+2))
im not understanding what you were saying there in your last response
before i have wrote there in numerator 2(x-2/ i now i have said that there is -2
so you need to solve it ?
than you need to suppose that x not can being -2 because than the denominator will be equal zero and than the fraction is undefined
but x=2 is right
like solution of it
yes i do understand now thank you
http://www.wolframalpha.com/input/?i=%28-2%28x%5E2-4%29%29%2F%283%28x%5E2%2B4x%2B4%29%29
yw my pleasure good luck bye

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