does anyone know how to sole this limit WITHOUT using L'Hôpital's rule? lim as x --> 1 from the right side, the function is -4/cube root of (1-x^2)

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does anyone know how to sole this limit WITHOUT using L'Hôpital's rule? lim as x --> 1 from the right side, the function is -4/cube root of (1-x^2)

Mathematics
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infinite
\[\lim_{x \rightarrow 1} \frac {-4}{\sqrt[3]{1 - x^2}}\]
Does the limit exist first of all?

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Hey Rogue, it is a right sided limit, but I think Ackhat may have nailed it. It makes sense that it would go to positive infinity. I think.
Thanks for your time Rogue and Ackhat. I greatly appreciate it.
Yeah, it is infinity if approached from the right. However, the over limit does not exist since the right & left limits are not equal. There really isn't any other way of doing this algebraically with out L'Hopital's, although you might be able to see it intuitively.

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