anonymous
  • anonymous
(b^-2/3)^9/2 I'm stumped on this problem. I'm simplifying by the laws of exponents and I can't have any negative exponents. I've got to this point and I'm not sure what to do next (b^-2/3)^9/2=(1/b^2/3)^9/2 any advice?
Mathematics
chestercat
  • chestercat
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jhonyy9
  • jhonyy9
you get b^(-3) = 1/b^3
jhonyy9
  • jhonyy9
first is b^(-18/6)
jhonyy9
  • jhonyy9
because (x^a)^b = x^(a*b)

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anonymous
  • anonymous
I think I may typed it in wrong...(b-2/3)9/2 (the fractions are exponents)
jhonyy9
  • jhonyy9
yes this is ok
jhonyy9
  • jhonyy9
so than you get -18/6 like exponent what equal -3
jhonyy9
  • jhonyy9
so b^-3 = 1/b^3
jhonyy9
  • jhonyy9
ok ?
anonymous
  • anonymous
got it! Thank you so much!!
jhonyy9
  • jhonyy9
yw good luck bye

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