## anonymous 4 years ago find the volume y=x^2, x = y^2 on x=-8

|dw:1328475204204:dw| outer radius is 8+sqrt(y) inner radius is 8+y^2 $V= \pi \int\limits_{0}^{1}(8+\sqrt{y})^{2}-(8+y^{2})^{2} dy$