## anonymous 4 years ago A car drives down a road in such a way that its velocity ( in m/s) at time t (seconds) is v(t) = 1 t^{1/2} + 3 Find the car's average velocity (in m/s) between t=3 and t=6.

1. anonymous

i think you need the total distance travelled divided by the time elapsed

2. anonymous

i.e.i think you need $\frac{1}{3}\int_3^6 \sqrt{t}+3 dt$

3. anonymous

$\frac{1}{3}\int_3^6 \sqrt{t}dt+\frac{1}{3}\times 9$ $\frac{1}{3}(4\sqrt{6}-2\sqrt{3})+3$

4. anonymous

thank u ! , i have been on that question for an hr!