## anonymous 4 years ago help

1. anonymous

$\int\limits_{?}^{?}\sqrt[3]{x ^{3}+1}*x ^{5}$

2. anonymous

the root is a 3

3. anonymous

try $u=x^3+1$

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the rest of it are basic integrals, don't forget to turn t to x in the end and ofcourse integration constant....

6. anonymous

$du=3x^2dx$ and so $\frac{1}{3}du = x^2dx$ now you have $x^5dx$ not $x^2dx$ but no matter since you can solve $u=x^3+1\iff u-1=x^3$ and integrate $\int\sqrt[3]{u}(u-1)du$