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anonymous

  • 4 years ago

Evaluate the limit as x-> infinity; lim sin (x)/x--> i think it's the limit DNE because as x-> lim sin (x) doesn't because as sin x continues to take on all values between -1 and 1 and doesn't approach any one UNIQUE number...but I could be wrong!

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  1. nenadmatematika
    • 4 years ago
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    you can use I think Americans use term squeeze rull. Wait one minute to draw you :D

  2. nenadmatematika
    • 4 years ago
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    |dw:1328476675396:dw|

  3. nenadmatematika
    • 4 years ago
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    you know that the limit of (1/x) and (-1/x) is zero when x goes to infinity, so sinx/x in the middle also goes to zero, so the limit is 0

  4. anonymous
    • 4 years ago
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    limit x > infiniity 1/x = 0 limit x > inf. sinx / x = 0

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