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anonymous
 4 years ago
Can someone plz help me out with inequality using polar coordinates?
anonymous
 4 years ago
Can someone plz help me out with inequality using polar coordinates?

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TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1um... not really sure if I get the question, but the area swept out by r is\[\frac38\le r\le\frac12\]and theta is just\[0\le\theta\le2\pi\]

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1no sorry inner r is 3/16

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1\[\frac3{16}\le r\le\frac12\]\[0\le\theta\le2\pi\]I suppose

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes that is the answer

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1do you need explanation?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0lol yes i dont understand how u got thise values

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1well polar coordinates are defined with radius and angle. Here are the diametersdw:1329346620272:dwso we know the radii are half this. therefor radius of any point on the washer is between 3/16inches (the radius of the inner circle) and 1/2inches (the radius of the outer circle)\[\frac3{16}\le r\le\frac12\]

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1329346791420:dwas for the angle, the washer is circular, so the angle has to sweep out a complete circle:\[0\le\theta\le2\pi\](we never go around the circle more than once, so no need to put more than 2pi))

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1if it was top half of a washer, the angle would be \[0\le\theta\le\pi\]if it was a disk (no hole in the middle) the radius would be\[0\le r\le\frac12\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh it is so simple ok Thanks for helping me out :)
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