anonymous
  • anonymous
Can someone plz help me out with inequality using polar coordinates?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
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TuringTest
  • TuringTest
um... not really sure if I get the question, but the area swept out by r is\[\frac38\le r\le\frac12\]and theta is just\[0\le\theta\le2\pi\]
TuringTest
  • TuringTest
no sorry inner r is 3/16

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TuringTest
  • TuringTest
\[\frac3{16}\le r\le\frac12\]\[0\le\theta\le2\pi\]I suppose
anonymous
  • anonymous
yes that is the answer
TuringTest
  • TuringTest
do you need explanation?
anonymous
  • anonymous
lol yes i dont understand how u got thise values
TuringTest
  • TuringTest
well polar coordinates are defined with radius and angle. Here are the diameters|dw:1329346620272:dw|so we know the radii are half this. therefor radius of any point on the washer is between 3/16inches (the radius of the inner circle) and 1/2inches (the radius of the outer circle)\[\frac3{16}\le r\le\frac12\]
anonymous
  • anonymous
ok got that
TuringTest
  • TuringTest
|dw:1329346791420:dw|as for the angle, the washer is circular, so the angle has to sweep out a complete circle:\[0\le\theta\le2\pi\](we never go around the circle more than once, so no need to put more than 2pi))
anonymous
  • anonymous
ok i think i get it
TuringTest
  • TuringTest
if it was top half of a washer, the angle would be \[0\le\theta\le\pi\]if it was a disk (no hole in the middle) the radius would be\[0\le r\le\frac12\]
anonymous
  • anonymous
ohhhh i see i get it
anonymous
  • anonymous
oh it is so simple ok Thanks for helping me out :)
TuringTest
  • TuringTest
anytime!

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