## anonymous 4 years ago Use the Quadratic Formula to solve the equation. 6 + 6x – x^2 = 0

1. anonymous

i got an answer involving a square root and got it wrong :(

2. Mertsj

$x=\frac{-6\pm \sqrt{6^2-4(-1)(6)}}{-2}$

3. anonymous

after that i got (-6+-√60)/2

4. anonymous

do you think the final answer should be (-6+-2√15)/2

5. Mertsj

$x=\frac{-6\pm \sqrt{60}}{-2}$

6. Mertsj

$x=\frac{-6\pm2\sqrt{15}}{-2}$

7. anonymous

should i divide the 6 by 2?

8. anonymous

-6/-2?

9. Mertsj

$x=3\pm \sqrt{15}$

10. anonymous

i was under the impression i was not to touch the number that is next to the radical if it is not seperated by a +- sign

11. Mertsj

You have two terms in the numerator. They can be reduced individually

12. anonymous

oo ok, thanks for your help

13. Mertsj

$x=\frac{-6}{-2}\pm\frac{2\sqrt{15}}{-2}$

14. Mertsj

yw

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