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anonymous

  • 4 years ago

50x^2-15x-5x=0. I think i did this right, but I'm not sure. What are the solutions and how do you get them.

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  1. Mertsj
    • 4 years ago
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    50x^2-20x=0 10x(5x-2)=0 10x=0 5x-2=0 x=0, 2/5

  2. anonymous
    • 4 years ago
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    thanks, are you sure? :) I got a different answer

  3. Mertsj
    • 4 years ago
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    Well, to begin with, I suspect that you posted the problem incorrectly.

  4. precal
    • 4 years ago
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    use the equation key on the lower left hand side to post your question

  5. anonymous
    • 4 years ago
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    ok jus a sec

  6. anonymous
    • 4 years ago
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    \[50x^3-15x^2-5x=0\]

  7. precal
    • 4 years ago
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    5x(10x^2-3x-1)=0 sorry talking to my boyfriend

  8. precal
    • 4 years ago
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    |dw:1328484552332:dw|

  9. precal
    • 4 years ago
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    |dw:1328484615926:dw|

  10. precal
    • 4 years ago
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    5x(5x+1)(2x-1)=0 5x=0 5x+1=0 2x-1=0 x=0 x=-1/5 x=1/2

  11. anonymous
    • 4 years ago
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    :D awesome thats what i got, thanks!

  12. precal
    • 4 years ago
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    I used an old jedi trick above to get rid of the number 10 I multiply it to 1. I had to put it back in by dividing..... did you see it?

  13. anonymous
    • 4 years ago
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    i think so

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