anonymous
  • anonymous
50x^2-15x-5x=0. I think i did this right, but I'm not sure. What are the solutions and how do you get them.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Mertsj
  • Mertsj
50x^2-20x=0 10x(5x-2)=0 10x=0 5x-2=0 x=0, 2/5
anonymous
  • anonymous
thanks, are you sure? :) I got a different answer
Mertsj
  • Mertsj
Well, to begin with, I suspect that you posted the problem incorrectly.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

precal
  • precal
use the equation key on the lower left hand side to post your question
anonymous
  • anonymous
ok jus a sec
anonymous
  • anonymous
\[50x^3-15x^2-5x=0\]
precal
  • precal
5x(10x^2-3x-1)=0 sorry talking to my boyfriend
precal
  • precal
|dw:1328484552332:dw|
precal
  • precal
|dw:1328484615926:dw|
precal
  • precal
5x(5x+1)(2x-1)=0 5x=0 5x+1=0 2x-1=0 x=0 x=-1/5 x=1/2
anonymous
  • anonymous
:D awesome thats what i got, thanks!
precal
  • precal
I used an old jedi trick above to get rid of the number 10 I multiply it to 1. I had to put it back in by dividing..... did you see it?
anonymous
  • anonymous
i think so

Looking for something else?

Not the answer you are looking for? Search for more explanations.