50x^2-15x-5x=0. I think i did this right, but I'm not sure. What are the solutions and how do you get them.

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

50x^2-15x-5x=0. I think i did this right, but I'm not sure. What are the solutions and how do you get them.

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

50x^2-20x=0 10x(5x-2)=0 10x=0 5x-2=0 x=0, 2/5
thanks, are you sure? :) I got a different answer
Well, to begin with, I suspect that you posted the problem incorrectly.

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

use the equation key on the lower left hand side to post your question
ok jus a sec
\[50x^3-15x^2-5x=0\]
5x(10x^2-3x-1)=0 sorry talking to my boyfriend
|dw:1328484552332:dw|
|dw:1328484615926:dw|
5x(5x+1)(2x-1)=0 5x=0 5x+1=0 2x-1=0 x=0 x=-1/5 x=1/2
:D awesome thats what i got, thanks!
I used an old jedi trick above to get rid of the number 10 I multiply it to 1. I had to put it back in by dividing..... did you see it?
i think so

Not the answer you are looking for?

Search for more explanations.

Ask your own question