find the intercepts of the graph of y=x^3-12x^2+32x (step by step response is greatly appreciated)
Stacey Warren - Expert brainly.com
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intercept with x axis: solve x^3-12x^2+32x=0 intercept with y axis: plug in x=0
so intercept point on y-axis are (0,0),(8,0) and (4,0) and when you plug in x=0 you get y=0 so that is an intecept point on x axis (the origin)
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these are your roots aka solutions aka x-intercepts
okay thanks! can you explain how you got the factor of x (x-8) (x-4)=0 please?
first x was factored out of the three terms since that is the GCF
second the trinomial was factored
look at your last term 32
what two numbers can you multiply to get 32 but when you add give you 12
(8)(4) = 32