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\[\int\limits_{3}^{8}\] xf''(x)

I need this broken down in layman terms

well, if we try to use this according to the definition of integration .. what can we get?

\[f(x)=\int f'(x)dx\]is the basic understanding of an integral

I don't understand what to do with the function values

it would appear to me that the 3 to 8 is the limits of integration

i might have to logout and back in to do this ...

ok

the math still aint processing from the latex on my end; you see normal equations on your end?

yes I can see them.

\[\int u dv =uv-\int v du\]

ok so would i just use xf''(x) as my function to integrate?

to wit:
u = x v = f'(x)
du = dx dv = f''(x) dx
yes

so when I integrate that is where the values that were given will be used?

\[\int xf''(x)=xf'(x)-\int f'(x)dx\]
\[\int xf''(x)=xf'(x)-f(x)\]

yes

im sure that looks alot more inspiring on your end lol

I shows up normal on my end

(8 f'(8)) - f(8) ) - (3 f'(3)-f(3)) should be our results

ok I didn't get that far but how did you get rid of the x?

ok i see know you used the limit that you are evaluating the integral?

yep

I got 53, is that correct?

I see my error, I am about to recalculate it

8*9 - 8 - (3*2-4)
72-8 - (6-4)
64 - 2 = 62

i hope that makes more sense, I have to be heading out now. good luck :)

I accidently used 8*8-9-)-(3*2-4). Thank you that was really helpful.