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anonymous
 4 years ago
Can some please help me with this:
Suppose f(3)=4, f(8)=8, f'(3)=2, f'(8)=9, and f'' is continuous.
Find the value of the definite integral
anonymous
 4 years ago
Can some please help me with this: Suppose f(3)=4, f(8)=8, f'(3)=2, f'(8)=9, and f'' is continuous. Find the value of the definite integral

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{3}^{8}\] xf''(x)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I need this broken down in layman terms

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1well, if we try to use this according to the definition of integration .. what can we get?

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1\[f(x)=\int f'(x)dx\]is the basic understanding of an integral

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I don't understand what to do with the function values

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1it would appear to me that the 3 to 8 is the limits of integration

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1\[\int_{3}^{8}x\ f''(x) dx\] is what we have to work with and all we have to determine is what to do with the "x" part

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1i might have to logout and back in to do this ...

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1the math still aint processing from the latex on my end; you see normal equations on your end?

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1good :) well then, lets see if we can move ahead with this then i think we can apply integration by parts to this .. just a gut felling

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1\[\int u dv =uv\int v du\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok so would i just use xf''(x) as my function to integrate?

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1to wit: u = x v = f'(x) du = dx dv = f''(x) dx yes

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so when I integrate that is where the values that were given will be used?

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1\[\int xf''(x)=xf'(x)\int f'(x)dx\] \[\int xf''(x)=xf'(x)f(x)\]

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1im sure that looks alot more inspiring on your end lol

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I shows up normal on my end

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1(8 f'(8))  f(8) )  (3 f'(3)f(3)) should be our results

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok I didn't get that far but how did you get rid of the x?

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1I didnt; i just used it in the integration by parts formula. there is no reason to get rid of it since the interval speaks in x to begin with

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok i see know you used the limit that you are evaluating the integral?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I got 53, is that correct?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I see my error, I am about to recalculate it

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.18*9  8  (3*24) 728  (64) 64  2 = 62

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1i hope that makes more sense, I have to be heading out now. good luck :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I accidently used 8*89)(3*24). Thank you that was really helpful.
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