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anonymous
 4 years ago
Find the average velocity of the object from points A to B, B to C , and A to C .
anonymous
 4 years ago
Find the average velocity of the object from points A to B, B to C , and A to C .

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1328486272548:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the points are a(0)=0 B(3)=25 c(6)=0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0My answer was 8.33,7, and zero

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Average velocity is given by [f(b)f(a)]/ba. So, for the first part, you'd want to do [f(3)f(0)]/30

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Then what is your question?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can you solve for it and tell me if our answers match up

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Okay. What I get is this: [250]/[3] = 8.333 That should be correct. Next, [f(6)f(3)]/(63) = (025)/3 = 8.333 And lastly: [f(6)f(0)]/(60) = (00)/6 = 0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0why is the second one 8.33

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ohh i apologize you are right thank you

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Well, a good way to look at this visually is to look at the graph: I'm assuming that that parabola is symmetrical. The curve comes up at the average velocity (slope) of 8.333. Then it comes back down with a similar slope, but negative. Hence the 8.333

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can you also help me with this For the intervals in above would the average speed be less than, equal to, or greater than the values you found in that Part?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yes, let me think for a moment.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Well, speed is different from velocity in the fact that velocity has direction. For example, the answer we got from A to B and B to C were the same except for their sign, right? That's because velocity is specific to the direction. A to B was going up, B to C was going down. Speed doesn't have that distinction. If you were to take the average speed from A to B, it'd be the same, but from B to C, speed doesn't care about direction; it would be 8.333 without the negative. Does that help?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so speed and velocity are the same magnitude but speed doesnt have direction . so speed tells you how fast you are going but not where you going

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yes! So do you think the average speed from B to C would be greater than, equal to, or less than the average velocity from B to C?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i think it would be greater

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0As far as I know, there would be no change from average velocity to average speed.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the answer choices has one of the them stay equal and the other 2 be greater

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Could you list the available choices? Thanks.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yah equal for ab, greater for bc, ac equal for bc, greater for ab ac equal for ac greater for ab ac

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oh. Okay. I think I know. So, we said that the velocity from A to B was 8.333, right? And we said that the velocity from B to C was 8.333. If you wanted to find the average for the entire thing, you would do (8.333+[8.333])/2. Make sense? You just add them (because they cover the entire graph and divide it to find average. Now, let's look at speed. We decided that from A to B stayed the same: 8.333, but we also decided that B to C changed to 8.333. Let's take the average:

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0(8.333+8.333)/2. This is the average from A to C! And it's greater with speed than it is velocity! That answers our question, I think. Same for AB, but greater for BC and AC.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0kinda of im a little confused to be honest

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Okay. Let's see if I can clear this up.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The average velocity of the entire curve can be obtained by adding together the avg velocity of one half of the curve and the other half and then dividing it by 2. Does that make sense?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Okay, and the average velocity for the entire curve is the same thing as average velocity from A to C, yes?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yah bevause the entire curve goes from a to c

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Our velocity: \[[8.333+(8.333)]\div2\] Our speed: [8.333+8.333]div2 Do you see and understand the difference?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oops.\[[8.333+8.333]\div2 \]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yah our velocity is zero and our speed is somethings else

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so it shows that it changed?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Right! And did it become greater than or less than? What do you think?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yes. So, in conclusion, we agreed that AB is the same, BC is greater and just now, AC is also greater. Is that an option?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yah you are right it is correct. so when we have tofind speed we have to always find the average

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Well, at this point, if you do not have a function for speed, you can only 'guess'. In Calculus it is possible to find the instantaneous speed, but otherwise you can only take averages.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can you explain quickly how you find the average of anything

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Well, you add up all of the terms (whatever they may be) and then divide it by the number of terms. Good?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but didnt we have 3 terms

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0No, we had 1 half of the curve and the other half of the curve, so we divided by two, right?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay . sohow do we know if we have a function for speed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Well, in the example you were just given a position function; the graph showed the position of the object over time. If the question had included a v(t) function, i.e. velocity over time, you could use it to find the velocity. Or, if the question had included a s(t) function, speed over time, you could use it to find the speed. Neither of these were included so we don't worry about it.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so just as a refresher what is a function

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0In general (and by no means is this an all inclusive definition) it is an equation that you put in an input (typically x) and receive and output (typically y). It has to pass the 'vertical line test' meaning that there are no two x values that equal the same y value.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay thank you for all your help and patience.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You're welcome :) Good luck!
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