anonymous
  • anonymous
How do I solve: (4x-1)(3x+7) = (5x-1)(2x+3)-6? The answer is supposed to be: -3+/-2√2.. how?
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
I got \[72x ^{2} + 103x -25 =0\] and do I use quadratic formula?
dumbcow
  • dumbcow
i get: 2x^2 +12x+2 = 0
nenadmatematika
  • nenadmatematika
something's wrong with your calculation...you can't get 72x^2...:D

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anonymous
  • anonymous
really?
dumbcow
  • dumbcow
but yes you would use quadratic formula
anonymous
  • anonymous
hooow>
dumbcow
  • dumbcow
(4x-1)(3x+7) = 12x^2 -3x +28x -7 (5x-1)(2x+3)-6 = 10x^2 -2x +15x -3 -6
anonymous
  • anonymous
for the (5x-1)(2x+3)-6, i don't multiply -6 to the rest of the terms?
dumbcow
  • dumbcow
only if its (-6)*(5x-1)(2x+3) the way its written it implies subtracting 6
anonymous
  • anonymous
really? ohh.. o.o thank you!!
dumbcow
  • dumbcow
yw

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