anonymous
  • anonymous
Prove the identity (sin^4)x - (cos^4)x = (sin^2)x - (cos^2)x
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
\[\sin ^{4}x - \cos ^{4}x = \sin ^{2}x - \cos ^{2}x\]
TuringTest
  • TuringTest
apply difference of squares to the left once, and look for an identity
anonymous
  • anonymous
sin^4x-cos^4x=(sin^2x+cos^2x )(sin^2x-cos^2x ).....(2) (sin^2x+cos^2x )=1.................(1) hence from 1 and 2 1((sin^2x-cos^2x )

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TuringTest
  • TuringTest
why use a double-angle formula? shivams' two-step answer is fine

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