anonymous
  • anonymous
Hey guys! Problem 1D8a... f(x)=ax+b, x>0 ; f(x)=sin2x, x
MIT 18.01 Single Variable Calculus (OCW)
  • Stacey Warren - Expert brainly.com
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chestercat
  • chestercat
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TuringTest
  • TuringTest
f'(0)=a=2cos(0)=2 so if a is not =2 it's not differentiable at zero
TuringTest
  • TuringTest
plus it's not differentiable if it's not continuous, which is the case for b not=0
anonymous
  • anonymous
Ok, just saw a topic below and realized and haven't got to the part when I can calculate f'(0-), so for me it didn't make sense that f'(x)=2cos(2x)... Just gonna move on and tackle it again later! I got the b part nonetheless... Thanks a lot for the help ;)

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TuringTest
  • TuringTest
oh yeah, the chain rule is later in the series but there are questions that require it in the beginning. They should fix that :/
TuringTest
  • TuringTest
...you could perhaps use a trig formula instead
anonymous
  • anonymous
|dw:1328490764769:dw| |dw:1328491513309:dw|
anonymous
  • anonymous
Got it! Thanks a lot :)
anonymous
  • anonymous
This is the value of a and b where it is differentiable....are you looking for the values where it is not?
anonymous
  • anonymous
Therefore if a is not equal to 2 or if b is not equal to zero, then the function is not differentiable.

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