lim x approaches 0 for f(x)=(1-x)/(x(1+xk)^(n-1))

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lim x approaches 0 for f(x)=(1-x)/(x(1+xk)^(n-1))

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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k is positive
\[\lim_{x \rightarrow 0}\frac{1-x}{x(1+xk)^{n-1}}\]
yes

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give me a second to think
wolfram is giving me +/- infinity
what about n
I'll type out the rest of the word problem
In an article on the local clustering of cell surface receptors, the researcher analyzed the limits of the function: (The function I put) X is the concentration of free receptors, n is the number of functional groups of cells, and k is a positive constant The function is also equal to C which is the concentration of free ligand in the medium
i think its supposed to represent a previous amount
yeah i don't know about all that stuff i'm sorry astro
what is this called?
i can try to find someone who knows about whatever this is
no problem- its just studying limits for now based around cell surface receptors
and we are assuming maybe n>1?
That would make sense
ok i think i got it one sec
\[\lim_{x \rightarrow 0^+}\frac{1-x}{x(1+xk)^{n-1}}=\infty \] since 1-x is negative for any values approaching 0 from the right but both the factors of the bottom are positive since k>0 we know nothing can be done to force f to be continuous at x=0 so we know from the right it approaches +infinity and from the left it approaches negative infinity since 1-x is positive at x approaches 0 from the left
as approaches*
Thank you, that makes sense to me
cool! :)
i'm glad i could help you with the math part lol

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