A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • 4 years ago

Find the equation of the tangent line to the graph of the function y=f(x)=x^2(x-2)^3 at the point with x=1.

  • This Question is Closed
  1. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    it is \[f (x)=x ^{2}\times(x-2)^{3}\] ???

  2. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes

  3. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    derive the function and evaluate in 1 and you'll have the pendient, replace 1 in the first function and you have the point, so you have the pendient and one point, you can get the equation (y-a)=m(x-b), sorry for my english I speak spanish XD

  4. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    How do I start to evaluate the function?

  5. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I mean, derive*

  6. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    step by step ...first: replace 1 in the function, what is the result?

  7. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    -1

  8. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok you have the point (1, -1) , remember the equation of a rect you need a point and the pendient, you have a point, now you need the pendient in x=1, the pendient in x=1 is the derivate of the function evaluate in 1, .. can you derive the function?

  9. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I don't know past here...

  10. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok the derivate of the function is : \[2x(x-3)^{3} + x ^{2}(3(x-2)^{2})\] if you evaluate in 1 the result is -13, I think, so you have the pendient m= -13 and the point (a,b)= (1, -1) .. the rect is (y-a)=m(x-b) and replace the values

  11. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    sorry i have a mistake is 2x(x-2)^3 but is the same idea

  12. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.