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top: x+3 right: x^2-3x left: x+7 bottom: 3x-3
Okay! Perimeter is defined by all of the sides added together, right?
I think so
So: \[55=(x+3)+(x^2-3)+(x+7)+(3x-3)\] 55, the perimeter is equal to all of the sides added together! We can combine like terms...
So then you have \[55=x^2+5x+4\] I think.
Can you solve for x?
Oh no! I made a mistake. one moment.
Which is then: x^2+2x+7
Set it equal to 55 and solve.
It says i need more than one answer, one for each side
Each side of what?
Well if you solve for x, then you put x back into the equation for each side. Does that make sense?
what is x? then i take that and put in each different equation?
Yes. I can help you solve for x.
ok thank you
So, you have 55=(x+3)+(x^2−3x)+(x+7)+(3x−3). This simplifies when you combine like terms to 55=x^2+2x+7. Can you solve it from that point by factoring or do you need more help?
I dont know, what do i do with 55? i can only solve the other side
Well, we can set the expression equal to zero: Move the 55 over to the right. So now, we have 0=x^2+2x-48. Do you see how I got that? Next, try to factor this; it works out nicely. Should give you two answers.
Yes, and ill solve that, be right back :)
6 and -8?
Yes! Okay, so we're talking about distance here. can we have a negative distance? Which solution do you think we should use?
Yes. So, what are your dimensions if you plug in x=6?
i got 9, 13, 15, and 18 total, are these correct?
That's what I got! Good work!
:D You're very welcome. Have a good night.