## anonymous 4 years ago 2-3i/1-2i

1. anonymous

conjugate

2. anonymous

$\frac{2-3i}{1-2i}\times \frac{1+2i}{1+2i}$ $\frac{(2-3i)(1+2i)}{1^2+2^2}$ then multiply in the numerator

3. anonymous

(2-3i/1-2i)*(1+2i/1+2i)

4. anonymous

$\frac{8+i}{5}=\frac{8}{5}+\frac{1}{5}i$

5. anonymous

got that far then once I multiplied it out I'm coming up with 2+9i/1+4i when the book says 8/5+1/5i

6. anonymous

how did you get the 8

7. anonymous

I am coming up with 2+7i/1+4i where did the 8 come from?