anonymous
  • anonymous
Law of Sines- The Ambiguous Case 1) m
Mathematics
  • Stacey Warren - Expert brainly.com
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chestercat
  • chestercat
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anonymous
  • anonymous
|dw:1328495762650:dw|
anonymous
  • anonymous
I have to find m
anonymous
  • anonymous
I don't get how to start. :/

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anonymous
  • anonymous
lets find the big triangle first. by the law of sines you have \[\frac{\sin(29)}{27}=\frac{\sin(B)}{31}\] \[\frac{31\sin(29)}{27}=\sin(B)\] \[\sin(B)=.5566\] rounded so \[B=\sin^{-1}(.5566)=33.82\]
anonymous
  • anonymous
|dw:1328496308131:dw|
anonymous
  • anonymous
sorry for the lousy picture, but you can see you have two choices for angle A
anonymous
  • anonymous
in big triangle angle A is 180-29-33.82 = 117.18
anonymous
  • anonymous
That first response was great definitely helped! But what number would be the opposite & what number would be the adj? Cause that will help me determine the # of triangles.
anonymous
  • anonymous
these are not right triangles so you do not have "opposite" and "adjacent"
anonymous
  • anonymous
i was looking at the largter triangle first and using the laws of sines, because the invese sine funcion on your calculator will not give you the bigger angle, only the one less that 90 degrees
anonymous
  • anonymous
My teacher gave us notes and it says if you have two sides & one opposite (NON-included) angle of a triangle then there are three possibilities:
anonymous
  • anonymous
|dw:1328496610821:dw|
anonymous
  • anonymous
How is this determined? opp \[\ge\] adj or opp \[\le\] adj
anonymous
  • anonymous
that is the larger triangle, and first we solve for B because you have angle C, side c, and side b
anonymous
  • anonymous
so you know three out of the 4 numbers for the ratio it is not a matter of "opposite" "adjacent" etc because these are not right triangles
anonymous
  • anonymous
i labled them with the side c opposite angle C, side a opposite angle A and side b opposite angle B
anonymous
  • anonymous
then you can use \[\frac{\sin(A)}{a}=\frac{\sin(B)}{b}=\frac{\sin(C)}{c}\][
anonymous
  • anonymous
and since we know side c, angle C, side b we have three out of the 4 numbers for the ratio here \[\frac{\sin(B)}{b}=\frac{\sin(C)}{c}\] allowing us to solve for angle B

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