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anonymous

  • 4 years ago

Please help me solve A developer wants to enclose a rectangular grassy lot that borders a city street for parking. If the developer has 272ft of fencing and does not fence the side along the street, what is the largest area that can be enclosed?

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  1. anonymous
    • 4 years ago
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    2w + l = 272 ft ----> l = -2w + 272 => A = w ( -2w + 272) = - 2w² + 272w The largest area happens when A' = 0 A' = - 4w + 272 = 0 ---> w = 272/4 = 68 ft ==> l = -2* 68 + 272 = 136 ft Thus largest area can be enclosed: A = 68 * 136 = 9248 ft²

  2. anonymous
    • 4 years ago
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    THANKS

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