A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
Please help me solve
A developer wants to enclose a rectangular grassy lot that borders a city street for parking. If the developer has 272ft of fencing and does not fence the side along the street, what is the largest area that can be enclosed?
anonymous
 4 years ago
Please help me solve A developer wants to enclose a rectangular grassy lot that borders a city street for parking. If the developer has 272ft of fencing and does not fence the side along the street, what is the largest area that can be enclosed?

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.02w + l = 272 ft > l = 2w + 272 => A = w ( 2w + 272) =  2w² + 272w The largest area happens when A' = 0 A' =  4w + 272 = 0 > w = 272/4 = 68 ft ==> l = 2* 68 + 272 = 136 ft Thus largest area can be enclosed: A = 68 * 136 = 9248 ft²
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.