anonymous
  • anonymous
Find the product: (x2 + 9x + 7)(3x^2 + 9x + 5) a.3x^4 + 36x^3 + 17x^2 + 18x + 3 b.3x^4 + 27x^3 + 81x^2 + 53x + 35 c.3x^4 + 36x^3 + 107x^2 + 108x + 35 d.3x^4 + 27x^3 + 107x^2 + 18x + 5
Mathematics
schrodinger
  • schrodinger
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Xishem
  • Xishem
Multiply each term in the first set of parenthesis with each term in the second set. You'll end up originally with nine terms, before you simplify. \[(x^2+9x+7)(3x^2+9x+5)\]\[3x^4+9x^3+5x^2+27x^3+81x^2+45x+21x^2+63x+35\]Now combine terms...\[3x^4+36x^3+107x^2+108x+35\]
anonymous
  • anonymous
thank you so much luis!!!!!(: and thank you xishem!

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