How would you find the standard equation of a circle, inscribed inside a square with the verticies (-12,10), (8,10), (8, -10), (-12,10)?

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How would you find the standard equation of a circle, inscribed inside a square with the verticies (-12,10), (8,10), (8, -10), (-12,10)?

Mathematics
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well at least we know that the radius of the circle is 10
The midpoint of the diagonals is (-2,0) and that would be the center of the circle so the equation must be:
wouldn't that be the diameter?

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Other answers:

\[(x+2)^2+y^2=100\]
Wouldn't what be the diameter?
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