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anonymous

  • 4 years ago

hi , i am having a lot of trouble with this problem any help would be appreciated A little cat, Bella, walks in a straight line, which we shall call the x axis, with the positive direction to the right. As an observant scientist, you make measurements of her motion and construct a graph of the little feline's velocity as a function of time. Find the x component of Bella's velocity at t = 4.00 s. give me a sec have to draw graph...

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  1. anonymous
    • 4 years ago
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    to see the graph i found the question online here it is http://www.cobaltss.net/forums/lounge-42/anyone-good-physics-151699/

  2. anonymous
    • 4 years ago
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    \[v(t)=\frac{-4}{3}t+8\]

  3. anonymous
    • 4 years ago
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    \[a(t)=\frac{-4}3{}\]

  4. anonymous
    • 4 years ago
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    a) t=4 v(t)=-16/3+8 v(t=4)=2.66

  5. anonymous
    • 4 years ago
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    can you please explain to me what the question is asking

  6. anonymous
    • 4 years ago
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    i mean how did you figure out the first equation you wrote

  7. anonymous
    • 4 years ago
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    ok, the line is passing (0,8) and (6,0) right

  8. anonymous
    • 4 years ago
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    yah

  9. anonymous
    • 4 years ago
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    and we know its slope is -8/6

  10. anonymous
    • 4 years ago
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    yah

  11. anonymous
    • 4 years ago
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    y=mx+n its formula

  12. anonymous
    • 4 years ago
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    okay

  13. anonymous
    • 4 years ago
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    put m=-8/6 and (0,8) or (6,0) to find n

  14. anonymous
    • 4 years ago
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    y=-8/6x+8=-4/3+8

  15. anonymous
    • 4 years ago
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    y=V(t) x=t

  16. anonymous
    • 4 years ago
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    so this is how find the velocity

  17. anonymous
    • 4 years ago
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    |dw:1328511634338:dw|

  18. anonymous
    • 4 years ago
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    and now you have v(t) so you can find v at any time

  19. anonymous
    • 4 years ago
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    yah

  20. anonymous
    • 4 years ago
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    do you know derivative

  21. anonymous
    • 4 years ago
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    kinda of

  22. anonymous
    • 4 years ago
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    this cat is negative accelating (deceleration ) and t=6 v=0 it means at t=6 it stops in a short time and going to opposite side(speed up)..

  23. anonymous
    • 4 years ago
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    dx/dt=v(t) dv/dt=a(t)

  24. anonymous
    • 4 years ago
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    that`s how I found a(t)

  25. anonymous
    • 4 years ago
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    ehats a(t)

  26. anonymous
    • 4 years ago
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    ehats?

  27. anonymous
    • 4 years ago
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    i means whats a(t)

  28. anonymous
    • 4 years ago
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    acceleration at t = 6.00 s.

  29. anonymous
    • 4 years ago
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    you need it for question c,d,e

  30. anonymous
    • 4 years ago
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    what is the difference between velocity and acceleration

  31. anonymous
    • 4 years ago
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    In physics, acceleration is the rate of change of velocity with time

  32. anonymous
    • 4 years ago
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    acceleration is always constant or zero

  33. anonymous
    • 4 years ago
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    if velocity is constant then a is zero

  34. anonymous
    • 4 years ago
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    in your question, v is not constant, it changes with time, so there is an accelation

  35. anonymous
    • 4 years ago
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    |dw:1328512464896:dw|

  36. anonymous
    • 4 years ago
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    |dw:1328512506539:dw|

  37. anonymous
    • 4 years ago
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    so if velocity is constant acceleration is zero if not it changes

  38. anonymous
    • 4 years ago
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    was i suppose to use this equation for this problem

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  39. anonymous
    • 4 years ago
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    so if velocity is constant acceleration is zero that's right

  40. anonymous
    • 4 years ago
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    can u take a look at the formula i attached

  41. anonymous
    • 4 years ago
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    you can use it. you know that a is constant and it is -4/3 already v0=8 v(x) we looking for at t=?

  42. anonymous
    • 4 years ago
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    sryy how do you know acceleration constant

  43. anonymous
    • 4 years ago
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    because a is slope of v, v is a line, slope doesnot change in time, it is constant

  44. anonymous
    • 4 years ago
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    as I said before a is zero or constant ALWAYS

  45. anonymous
    • 4 years ago
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    |dw:1328513106159:dw|

  46. anonymous
    • 4 years ago
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    how do you know if it is zero or constant

  47. anonymous
    • 4 years ago
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    take a look graph which I drew at up..

  48. anonymous
    • 4 years ago
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    its constant

  49. anonymous
    • 4 years ago
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    ok, there is always two stuation,

  50. anonymous
    • 4 years ago
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    |dw:1328513296298:dw|

  51. anonymous
    • 4 years ago
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    this one is first stuation..

  52. anonymous
    • 4 years ago
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    the velocity is increasing then decreasing

  53. anonymous
    • 4 years ago
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    velocity is not constant

  54. anonymous
    • 4 years ago
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    yah

  55. anonymous
    • 4 years ago
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    |dw:1328513379149:dw|

  56. anonymous
    • 4 years ago
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    this is secend stuation, v is constant

  57. anonymous
    • 4 years ago
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    yah

  58. anonymous
    • 4 years ago
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    your problem is first one..

  59. anonymous
    • 4 years ago
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    yah . the last graph you drew show that velocity is zero

  60. anonymous
    • 4 years ago
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    but I drew speed up, yours is speed down

  61. anonymous
    • 4 years ago
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    yah i can see that

  62. anonymous
    • 4 years ago
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    and it has inital velocity which is 8

  63. anonymous
    • 4 years ago
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    so everything is clear now

  64. anonymous
    • 4 years ago
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    so you said acceler is alway zero or constant is velocity is constant its zero. what if velocity is zero

  65. anonymous
    • 4 years ago
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    it means that car remains stop, no act no acce..

  66. anonymous
    • 4 years ago
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    and if acceleration is zero what does that tell you about your car

  67. anonymous
    • 4 years ago
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    if you are driving a car 50 mile/h all the way then your accel is 0 if you are speeding 50 to 100 in 1 min then there is accele. which is const..

  68. anonymous
    • 4 years ago
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    your car is stop

  69. anonymous
    • 4 years ago
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    i apologize for making you repeat but if you have constant velocity , then the acceleration of your car would be...

  70. anonymous
    • 4 years ago
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    http://wiki.answers.com/Q/What_causes_acceleration_to_increase

  71. anonymous
    • 4 years ago
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    0

  72. anonymous
    • 4 years ago
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    |dw:1328514179090:dw|

  73. anonymous
    • 4 years ago
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    constant velocity

  74. anonymous
    • 4 years ago
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    v doesnt change with time, so a is zero

  75. anonymous
    • 4 years ago
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    so the car is stopped?

  76. anonymous
    • 4 years ago
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    because acceleration is zero

  77. anonymous
    • 4 years ago
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    no, acceleration is zero doesnot require v is zero, v can be zero or constant, either way a is zero

  78. anonymous
    • 4 years ago
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    okay got it thank you

  79. anonymous
    • 4 years ago
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    can you give me some help with the next part

  80. anonymous
    • 4 years ago
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    I need it see it, I cant promise..

  81. anonymous
    • 4 years ago
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    so if i need to find x component of her acceleration at t = 4.00 s.

  82. anonymous
    • 4 years ago
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    i know that her acceleration is constant

  83. anonymous
    • 4 years ago
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    yes, her a is always -4/3 constant you see a(t)=-4/3 doesnot depent on t

  84. anonymous
    • 4 years ago
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    so whatever you plug into t, it will always will be -4/3

  85. anonymous
    • 4 years ago
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    yes.. but for accel right

  86. anonymous
    • 4 years ago
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    i mean whatever you plug in for t into the equation: y=-4/3t+8

  87. anonymous
    • 4 years ago
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    y=-4/3t+8 this eq. is for finding v at some certain time v(t)=-4/3t+8 a and b you need to use this eq. a(t)=-4/3 c,d,e use this formula

  88. anonymous
    • 4 years ago
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    i dont know what to do

  89. anonymous
    • 4 years ago
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    a) t=4 v=(-4/3)*4+8=2.66 is that right

  90. anonymous
    • 4 years ago
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    yah

  91. anonymous
    • 4 years ago
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    or v=v0+at v=8-(4/3)*4

  92. anonymous
    • 4 years ago
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    solve the same way t=7

  93. anonymous
    • 4 years ago
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    ill be back in ahour my battey is low

  94. anonymous
    • 4 years ago
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    ok..

  95. anonymous
    • 4 years ago
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    maybe I can't stay that long..

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