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to see the graph i found the question online here it is http://www.cobaltss.net/forums/lounge-42/anyone-good-physics-151699/
a) t=4 v(t)=-16/3+8 v(t=4)=2.66
can you please explain to me what the question is asking
i mean how did you figure out the first equation you wrote
ok, the line is passing (0,8) and (6,0) right
and we know its slope is -8/6
y=mx+n its formula
put m=-8/6 and (0,8) or (6,0) to find n
so this is how find the velocity
and now you have v(t) so you can find v at any time
do you know derivative
this cat is negative accelating (deceleration ) and t=6 v=0 it means at t=6 it stops in a short time and going to opposite side(speed up)..
that`s how I found a(t)
i means whats a(t)
acceleration at t = 6.00 s.
you need it for question c,d,e
what is the difference between velocity and acceleration
In physics, acceleration is the rate of change of velocity with time
acceleration is always constant or zero
if velocity is constant then a is zero
in your question, v is not constant, it changes with time, so there is an accelation
so if velocity is constant acceleration is zero if not it changes
so if velocity is constant acceleration is zero that's right
can u take a look at the formula i attached
you can use it. you know that a is constant and it is -4/3 already v0=8 v(x) we looking for at t=?
sryy how do you know acceleration constant
because a is slope of v, v is a line, slope doesnot change in time, it is constant
as I said before a is zero or constant ALWAYS
how do you know if it is zero or constant
take a look graph which I drew at up..
ok, there is always two stuation,
this one is first stuation..
the velocity is increasing then decreasing
velocity is not constant
this is secend stuation, v is constant
your problem is first one..
yah . the last graph you drew show that velocity is zero
but I drew speed up, yours is speed down
yah i can see that
and it has inital velocity which is 8
so everything is clear now
so you said acceler is alway zero or constant is velocity is constant its zero. what if velocity is zero
it means that car remains stop, no act no acce..
and if acceleration is zero what does that tell you about your car
if you are driving a car 50 mile/h all the way then your accel is 0 if you are speeding 50 to 100 in 1 min then there is accele. which is const..
your car is stop
i apologize for making you repeat but if you have constant velocity , then the acceleration of your car would be...
v doesnt change with time, so a is zero
so the car is stopped?
because acceleration is zero
no, acceleration is zero doesnot require v is zero, v can be zero or constant, either way a is zero
okay got it thank you
can you give me some help with the next part
I need it see it, I cant promise..
so if i need to find x component of her acceleration at t = 4.00 s.
i know that her acceleration is constant
yes, her a is always -4/3 constant you see a(t)=-4/3 doesnot depent on t
so whatever you plug into t, it will always will be -4/3
yes.. but for accel right
i mean whatever you plug in for t into the equation: y=-4/3t+8
y=-4/3t+8 this eq. is for finding v at some certain time v(t)=-4/3t+8 a and b you need to use this eq. a(t)=-4/3 c,d,e use this formula
i dont know what to do
a) t=4 v=(-4/3)*4+8=2.66 is that right
or v=v0+at v=8-(4/3)*4
solve the same way t=7
ill be back in ahour my battey is low
maybe I can't stay that long..