anonymous
  • anonymous
hi , i am having a lot of trouble with this problem any help would be appreciated A little cat, Bella, walks in a straight line, which we shall call the x axis, with the positive direction to the right. As an observant scientist, you make measurements of her motion and construct a graph of the little feline's velocity as a function of time. Find the x component of Bella's velocity at t = 4.00 s. give me a sec have to draw graph...
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
to see the graph i found the question online here it is http://www.cobaltss.net/forums/lounge-42/anyone-good-physics-151699/
anonymous
  • anonymous
\[v(t)=\frac{-4}{3}t+8\]
anonymous
  • anonymous
\[a(t)=\frac{-4}3{}\]

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anonymous
  • anonymous
a) t=4 v(t)=-16/3+8 v(t=4)=2.66
anonymous
  • anonymous
can you please explain to me what the question is asking
anonymous
  • anonymous
i mean how did you figure out the first equation you wrote
anonymous
  • anonymous
ok, the line is passing (0,8) and (6,0) right
anonymous
  • anonymous
yah
anonymous
  • anonymous
and we know its slope is -8/6
anonymous
  • anonymous
yah
anonymous
  • anonymous
y=mx+n its formula
anonymous
  • anonymous
okay
anonymous
  • anonymous
put m=-8/6 and (0,8) or (6,0) to find n
anonymous
  • anonymous
y=-8/6x+8=-4/3+8
anonymous
  • anonymous
y=V(t) x=t
anonymous
  • anonymous
so this is how find the velocity
anonymous
  • anonymous
|dw:1328511634338:dw|
anonymous
  • anonymous
and now you have v(t) so you can find v at any time
anonymous
  • anonymous
yah
anonymous
  • anonymous
do you know derivative
anonymous
  • anonymous
kinda of
anonymous
  • anonymous
this cat is negative accelating (deceleration ) and t=6 v=0 it means at t=6 it stops in a short time and going to opposite side(speed up)..
anonymous
  • anonymous
dx/dt=v(t) dv/dt=a(t)
anonymous
  • anonymous
that`s how I found a(t)
anonymous
  • anonymous
ehats a(t)
anonymous
  • anonymous
ehats?
anonymous
  • anonymous
i means whats a(t)
anonymous
  • anonymous
acceleration at t = 6.00 s.
anonymous
  • anonymous
you need it for question c,d,e
anonymous
  • anonymous
what is the difference between velocity and acceleration
anonymous
  • anonymous
In physics, acceleration is the rate of change of velocity with time
anonymous
  • anonymous
acceleration is always constant or zero
anonymous
  • anonymous
if velocity is constant then a is zero
anonymous
  • anonymous
in your question, v is not constant, it changes with time, so there is an accelation
anonymous
  • anonymous
|dw:1328512464896:dw|
anonymous
  • anonymous
|dw:1328512506539:dw|
anonymous
  • anonymous
so if velocity is constant acceleration is zero if not it changes
anonymous
  • anonymous
was i suppose to use this equation for this problem
1 Attachment
anonymous
  • anonymous
so if velocity is constant acceleration is zero that's right
anonymous
  • anonymous
can u take a look at the formula i attached
anonymous
  • anonymous
you can use it. you know that a is constant and it is -4/3 already v0=8 v(x) we looking for at t=?
anonymous
  • anonymous
sryy how do you know acceleration constant
anonymous
  • anonymous
because a is slope of v, v is a line, slope doesnot change in time, it is constant
anonymous
  • anonymous
as I said before a is zero or constant ALWAYS
anonymous
  • anonymous
|dw:1328513106159:dw|
anonymous
  • anonymous
how do you know if it is zero or constant
anonymous
  • anonymous
take a look graph which I drew at up..
anonymous
  • anonymous
its constant
anonymous
  • anonymous
ok, there is always two stuation,
anonymous
  • anonymous
|dw:1328513296298:dw|
anonymous
  • anonymous
this one is first stuation..
anonymous
  • anonymous
the velocity is increasing then decreasing
anonymous
  • anonymous
velocity is not constant
anonymous
  • anonymous
yah
anonymous
  • anonymous
|dw:1328513379149:dw|
anonymous
  • anonymous
this is secend stuation, v is constant
anonymous
  • anonymous
yah
anonymous
  • anonymous
your problem is first one..
anonymous
  • anonymous
yah . the last graph you drew show that velocity is zero
anonymous
  • anonymous
but I drew speed up, yours is speed down
anonymous
  • anonymous
yah i can see that
anonymous
  • anonymous
and it has inital velocity which is 8
anonymous
  • anonymous
so everything is clear now
anonymous
  • anonymous
so you said acceler is alway zero or constant is velocity is constant its zero. what if velocity is zero
anonymous
  • anonymous
it means that car remains stop, no act no acce..
anonymous
  • anonymous
and if acceleration is zero what does that tell you about your car
anonymous
  • anonymous
if you are driving a car 50 mile/h all the way then your accel is 0 if you are speeding 50 to 100 in 1 min then there is accele. which is const..
anonymous
  • anonymous
your car is stop
anonymous
  • anonymous
i apologize for making you repeat but if you have constant velocity , then the acceleration of your car would be...
anonymous
  • anonymous
http://wiki.answers.com/Q/What_causes_acceleration_to_increase
anonymous
  • anonymous
0
anonymous
  • anonymous
|dw:1328514179090:dw|
anonymous
  • anonymous
constant velocity
anonymous
  • anonymous
v doesnt change with time, so a is zero
anonymous
  • anonymous
so the car is stopped?
anonymous
  • anonymous
because acceleration is zero
anonymous
  • anonymous
no, acceleration is zero doesnot require v is zero, v can be zero or constant, either way a is zero
anonymous
  • anonymous
okay got it thank you
anonymous
  • anonymous
can you give me some help with the next part
anonymous
  • anonymous
I need it see it, I cant promise..
anonymous
  • anonymous
so if i need to find x component of her acceleration at t = 4.00 s.
anonymous
  • anonymous
i know that her acceleration is constant
anonymous
  • anonymous
yes, her a is always -4/3 constant you see a(t)=-4/3 doesnot depent on t
anonymous
  • anonymous
so whatever you plug into t, it will always will be -4/3
anonymous
  • anonymous
yes.. but for accel right
anonymous
  • anonymous
i mean whatever you plug in for t into the equation: y=-4/3t+8
anonymous
  • anonymous
y=-4/3t+8 this eq. is for finding v at some certain time v(t)=-4/3t+8 a and b you need to use this eq. a(t)=-4/3 c,d,e use this formula
anonymous
  • anonymous
i dont know what to do
anonymous
  • anonymous
a) t=4 v=(-4/3)*4+8=2.66 is that right
anonymous
  • anonymous
yah
anonymous
  • anonymous
or v=v0+at v=8-(4/3)*4
anonymous
  • anonymous
solve the same way t=7
anonymous
  • anonymous
ill be back in ahour my battey is low
anonymous
  • anonymous
ok..
anonymous
  • anonymous
maybe I can't stay that long..

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