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anonymous
 4 years ago
Rotate the region bounded by the given curves about the given line and find the volume resulting solid.
x=1+y^2 and the xaxis from x=1 to x=5 about y=3
anonymous
 4 years ago
Rotate the region bounded by the given curves about the given line and find the volume resulting solid. x=1+y^2 and the xaxis from x=1 to x=5 about y=3

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1328507665468:dw we need the function in terms of x, solving for y y = sqrt(x1) outer radius(R) = 3 inner radius(r) = 3sqrt(x1) \[V = \pi \int\limits_{1}^{5}3^{2} (3\sqrt{x1})^{2} dx\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Is this using disk or shell method?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0disk or washer method

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Do you know how to do it using shell?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0each vertical crosssection is a ring with outer circle and inner circle

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i can try...i primarily use the disk method though hold on

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok radius = 3y height = 5(y^2 +1) = 4y^2 \[V = 2\pi \int\limits_{0}^{2}(3y)(4y^{2}) dy\]
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