If I have 741.7kg of cranberries, that have 87% moisture content calculate the amount of water removed. The desired moisture content of cranberry sauce is 82% moisture content

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- anonymous

- katieb

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- King

36.083 kilos?

- King

is it rite?

- RagingSquirrel

96.421

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- King

hw raging squirell?

- RagingSquirrel

%13 percent of 741.7

- anonymous

sorry i made a mistake i have to calculate the water loss from the total cranberries which is 775kg

- RagingSquirrel

So its %13 or %18?

- anonymous

OMG it's really late I just read the question my original post was correct!!! 741.7

- RagingSquirrel

Haha, i'm pretty sure your answer is 741.7 or 142 rounded.

- anonymous

no 74107 is the amount of cranberries i have. I need to know how much water is removed from that 741.7

- anonymous

that's ok I'm really confused!!!!

- RagingSquirrel

Ohhh! I see it now!
645.279 is your answer.

- RagingSquirrel

That's percent by the way.
Dont forget to hit "good answer" if i helped you out!

- anonymous

water = moist content - souce
0.87 - 0.82 = 0.05
water weight = 0.05 times 741.7 = 37.085 kg

- anonymous

you are welcome

- anonymous

which is the answer that I got...my problem is i don't know if it's right!!!

- anonymous

Hermione .. Use your magic stick and ...and see what no.s say... my answer so similar to the first answer .. its the basic..its no so hard question here under clarification

- anonymous

|dw:1328517925571:dw|

- anonymous

|dw:1328518002581:dw|

- anonymous

|dw:1328518064181:dw|

- anonymous

5% = water and this is it !

- anonymous

you have to find what 5 % represent
5% of 741.7
0.05 * 741.7 = 37.085 kg

- Mertsj

Waleed is correct.

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