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anonymous

  • 4 years ago

Compute f'(a). f(x) = x^2 + 11x, when a = 6

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  1. anonymous
    • 4 years ago
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    f ' (a)

  2. campbell_st
    • 4 years ago
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    find f'(x) = 2x + 11 then substitute x = 6 into the derivative to find f'(a)

  3. anonymous
    • 4 years ago
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    12+11 = 23

  4. anonymous
    • 4 years ago
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    did you all use the power rule? and what about this... Find f(3) and f'(3), assuming that the tangent line to y = f(x) at a = 3 has equation y = 6x + 8

  5. anonymous
    • 4 years ago
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    how would you find the tangent line equation if you knew f '(X) or just f(x)

  6. campbell_st
    • 4 years ago
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    f'(x) at a point x = 6 will give the gradient of that tangent at x = 6..... sub x = 6 into the original equation to find the y value... then you have the gradient and point... which can be used the the point slope formula y - f(a) = f'(a)(x - a) to get the equation of the tangent

  7. anonymous
    • 4 years ago
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    so what is a?

  8. campbell_st
    • 4 years ago
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    in your example where x = 3 then y - f(3) = f'(3)(x-3)

  9. anonymous
    • 4 years ago
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    so 26 - 26 = 6 - 3?

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