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anonymous

  • 4 years ago

How do i determin the x and y intercepts of y=-x^3. can you show the formula for this?

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  1. anonymous
    • 4 years ago
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    put x=0 tell me what you get

  2. campbell_st
    • 4 years ago
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    for intercepts.... let x = 0 and solve for y gives y=intercept.... let y = 0 and solve for x gives the x intercept... y - intercept y = 0,.... x-intercept is x = 0

  3. campbell_st
    • 4 years ago
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    here is the sketch of the graph |dw:1328512947772:dw|

  4. anonymous
    • 4 years ago
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    i got 0

  5. anonymous
    • 4 years ago
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    x=0 y=0, Hence y intercept is 0 similarly put y=0 you get x=0 hence x intercept is zero

  6. anonymous
    • 4 years ago
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    Refer the graph

  7. anonymous
    • 4 years ago
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    do i do the same with 1,2,3under x intercept

  8. anonymous
    • 4 years ago
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    Yes

  9. anonymous
    • 4 years ago
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    ok so what if I have x=y^3-1

  10. anonymous
    • 4 years ago
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    do i just plug 0,1,2,3 in for x

  11. Directrix
    • 4 years ago
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    x=y^3-1 y^3 = x + 1 y = cube root of (x + 1) x-intercept Let y = 0 0 = cube root of (x + 1) 0^3 = [cube root of (x + 1)] ^ 3 0 = x + 1 x = -1 x-intercept (-1,0) y-intercept Let x = 0 y = cube root of (x + 1) y = cube root of (0 + 1) y = 1 y-intercept (0,1)

  12. Directrix
    • 4 years ago
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    |dw:1328535508756:dw| Graph at link above.

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