anonymous
  • anonymous
How do i determin the x and y intercepts of y=-x^3. can you show the formula for this?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
put x=0 tell me what you get
campbell_st
  • campbell_st
for intercepts.... let x = 0 and solve for y gives y=intercept.... let y = 0 and solve for x gives the x intercept... y - intercept y = 0,.... x-intercept is x = 0
campbell_st
  • campbell_st
here is the sketch of the graph |dw:1328512947772:dw|

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anonymous
  • anonymous
i got 0
anonymous
  • anonymous
x=0 y=0, Hence y intercept is 0 similarly put y=0 you get x=0 hence x intercept is zero
anonymous
  • anonymous
Refer the graph
anonymous
  • anonymous
do i do the same with 1,2,3under x intercept
anonymous
  • anonymous
Yes
anonymous
  • anonymous
ok so what if I have x=y^3-1
anonymous
  • anonymous
do i just plug 0,1,2,3 in for x
Directrix
  • Directrix
x=y^3-1 y^3 = x + 1 y = cube root of (x + 1) x-intercept Let y = 0 0 = cube root of (x + 1) 0^3 = [cube root of (x + 1)] ^ 3 0 = x + 1 x = -1 x-intercept (-1,0) y-intercept Let x = 0 y = cube root of (x + 1) y = cube root of (0 + 1) y = 1 y-intercept (0,1)
Directrix
  • Directrix
|dw:1328535508756:dw| Graph at link above.

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