anonymous
  • anonymous
in second law of motion 's' is distance or displacement
Physics
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
newtonian law ?
JamesJ
  • JamesJ
This law? \[ s = ut + \frac{1}{2}at^2 \] or \[ s = s_0 + v_0t + \frac{1}{2}at^2 \] Here, \( s \) is displacement.
anonymous
  • anonymous
s represents displacement but can some times be considered to be used as distance

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
relation that you want isn't law it's a equation of motion
JamesJ
  • JamesJ
Yes, technically what I've written isn't a Law of Motion, but just an equation of motion. In the three Newtonian Laws, there is no variable "s", that's why I went to one of the kinematic equations of motion instead.

Looking for something else?

Not the answer you are looking for? Search for more explanations.