anonymous
  • anonymous
How to determine if a reaction is a redox reaction? I need to know how... I've got a test about it tomorrow.. Also how to determine which is oxidized and reduced? Please help me.Thanks.
Chemistry
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
If there is change in oxidation state of a compound then there is a redox reaction. If a compoun's oxidation number has increased then it is getting oxidized, if its oxidation number has decreased it has been reduced.
anonymous
  • anonymous
Do you know how to calculate oxidation number?
anonymous
  • anonymous
no

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Rules for deciding oxidation number. Anything in elemental state is 0 (eg., Cu or Na or O2) All alkali metals(Na,K,Li,Rb) in any compunds are +1. eg, NaCl. Oxygen is always -2.(except O2 and O3). Hydrogen is always +1. All other elements areobtained by balancing oxidation number and charge
anonymous
  • anonymous
ok. how do i know which is oxidized and which is reduced?
anonymous
  • anonymous
Lets do some xamples CuSO4 + Zn-> ZnSO4+ Cu. Can you tell me all oxidation number of all compounds.
anonymous
  • anonymous
I'll do this one for you, Reactants, In first compound, SO4 is 2- charge since CuSO4 is neutral so oxidation number of Cu in CuSO4 is 2+. Now Zn is in elemental state hence it would be 0. Products, In ZnSO4 again Zn is Zn2+ and Cu is 0. Did you understand till here?
anonymous
  • anonymous
yep, i got it there
anonymous
  • anonymous
Fine So now in reactants side if you see Cu is 2+ but in products it is 0. This implies there is a redox reaction. Now whichever elemnts oxidation number is increasing it gets oxidized whichever oxidation number is getting decreased it is gettting reduced. So here Cu becomes from 2+ to 0 that means it got reduced while Zn went from 0 to 2+ which means it got oxidized.
anonymous
  • anonymous
wow, thanks.. i got it already Just one more question, how do you determine the reducing agent and the oxidizing agent?
anonymous
  • anonymous
Whatever gets oxidized is the reducing agent. Whatever gets reduced is oxidizing agent.
anonymous
  • anonymous
Here Zn is the reducing agent as it got oxidized.
anonymous
  • anonymous
ok, thanks :))
anonymous
  • anonymous
No problem.

Looking for something else?

Not the answer you are looking for? Search for more explanations.