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anonymous

  • 4 years ago

6th question: Find lim square root of x+4-2 over x, x->0.

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  1. anonymous
    • 4 years ago
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    pls help me guys pls :(

  2. ash2326
    • 4 years ago
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    \[\lim_{x->0} \frac{\sqrt{x+4}-2}{x}\] is this your question?

  3. nenadmatematika
    • 4 years ago
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    |dw:1328534324529:dw|

  4. anonymous
    • 4 years ago
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    yes thats my question thanks for your help.

  5. ash2326
    • 4 years ago
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    muiltiply numerator and denominator by \(\sqrt{x+4}+2\) so we get \[\lim_{x->0} \frac{x+4-4}{(\sqrt{x+4}+2)x}\] we get now \[\lim_{x->0} \frac{\cancel{x}}{(\sqrt{x+4}+2)\cancel{x}}\] we get finally \[\lim_{x->0} \frac{1}{(\sqrt{0+4}+2)}\] we get \[\frac{1}{2+2}\] or \[\frac{1}{4}\]

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