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anonymous
 4 years ago
6th question: Find lim square root of x+42 over x, x>0.
anonymous
 4 years ago
6th question: Find lim square root of x+42 over x, x>0.

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0pls help me guys pls :(

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.0\[\lim_{x>0} \frac{\sqrt{x+4}2}{x}\] is this your question?

nenadmatematika
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1328534324529:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes thats my question thanks for your help.

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.0muiltiply numerator and denominator by \(\sqrt{x+4}+2\) so we get \[\lim_{x>0} \frac{x+44}{(\sqrt{x+4}+2)x}\] we get now \[\lim_{x>0} \frac{\cancel{x}}{(\sqrt{x+4}+2)\cancel{x}}\] we get finally \[\lim_{x>0} \frac{1}{(\sqrt{0+4}+2)}\] we get \[\frac{1}{2+2}\] or \[\frac{1}{4}\]
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