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anonymous
 4 years ago
find the equation of a circle in standard form where 6,2 and 4,4 are endpoints of a diameter
anonymous
 4 years ago
find the equation of a circle in standard form where 6,2 and 4,4 are endpoints of a diameter

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Directrix
 4 years ago
Best ResponseYou've already chosen the best response.0The length of the diameter is (used the distance formula) = 2 times Square Root of 34. The radius is, then, √ (34) The midpoint of the diameter is the center of the circle and will give the (h,k). (64)/2 gives 1 for h and (2+4)/2 yields 1 for k. (x  1) ^2 + (y  1) ^2 = √ (34) ^2 (x  1) ^2 + (y  1) ^2 = 34

Directrix
 4 years ago
Best ResponseYou've already chosen the best response.0See the graph of the circle at the link: http://www.wolframalpha.com/input/?i=%28x++1%29+%5E2++%2B+%28y++1%29+%5E2+%3D+34
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