anonymous
  • anonymous
sin25° = a and cos40°=b Express the following in terms of a and b (1-tan155° sin295° ) / (tan410° cos 230° )
Mathematics
schrodinger
  • schrodinger
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JamesJ
  • JamesJ
You've got it. Great.
anonymous
  • anonymous
yoo
anonymous
  • anonymous
I just click wrongly :(

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anonymous
  • anonymous
\(\tan 155 = \tan(180-25) =\cdots \)
JamesJ
  • JamesJ
Yes, for each of the trig terms, you want to figure out how to write them as differences like this from standard trig functions. For example, with the one above: because tan(180) = 0 and tan(-x) = -tan(x), it follows that tan(180-25) = [ tan(180) - tan(25) ] / [ 1 - tan(180).tan(-25) ] = - tan(25) = - sin(25)/sqrt(1-sin^2(25)) = - a/sqrt(1-a^2)

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