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anonymous

  • 4 years ago

sin25° = a and cos40°=b Express the following in terms of a and b (1-tan155° sin295° ) / (tan410° cos 230° )

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  1. JamesJ
    • 4 years ago
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    You've got it. Great.

  2. anonymous
    • 4 years ago
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    yoo

  3. anonymous
    • 4 years ago
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    I just click wrongly :(

  4. anonymous
    • 4 years ago
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    \(\tan 155 = \tan(180-25) =\cdots \)

  5. JamesJ
    • 4 years ago
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    Yes, for each of the trig terms, you want to figure out how to write them as differences like this from standard trig functions. For example, with the one above: because tan(180) = 0 and tan(-x) = -tan(x), it follows that tan(180-25) = [ tan(180) - tan(25) ] / [ 1 - tan(180).tan(-25) ] = - tan(25) = - sin(25)/sqrt(1-sin^2(25)) = - a/sqrt(1-a^2)

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