anonymous
  • anonymous
The label on a bottle reads "MOH", and you set out to find the identity of the metal (M). Assuming that this is an alkali metal hydroxide, you weigh out 1.67g of the solid. It takes 0.0418L of 1.00M HCl to titrate the mtal hydroxide. What is the identity of the solid?
Chemistry
chestercat
  • chestercat
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

JFraser
  • JFraser
If you assume that "M" is a group 1 metal, then the balanced reaction will be \[MOH + HCl \rightarrow MCl + H{_2}O\] you know t he volume and concentration of acid added, so you know moles of acid added. You know the reaction is 1:1, so the moles of acid will be the same as the moles of metal "M"OH used. You know the mass of metal hydroxide used, and you know the moles used, so divide mass/mols to get molar mass and identify the compound.\[vol Acid * (\frac{mol acid}{vol acid})* (\frac{mol MOH}{mol acid}) = moles MOH used\] \[MM = \frac{mass MOH used}{moles MOH calculated}\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.