can someone explain how to find values of the six trigonometric functions when given: "Θ lies in Quadrant II. tan(Θ)=-24/7"

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can someone explain how to find values of the six trigonometric functions when given: "Θ lies in Quadrant II. tan(Θ)=-24/7"

Mathematics
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what the answer?
yeah, i'm not sure how to find it and i have four other problems for homework like it so i was wondering if someone could explain. do you knw?
u want the value of \[\Theta\]??

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Other answers:

no i need to find the other six trigonometric functions by using the function of tan(Θ)
|dw:1328543195617:dw|
\[\sin \theta=\frac{side opposite}{hypotenuse}=\frac{24}{25}\]
\[\cos \theta=\frac{side adjacent}{hypotenuse}=\frac{-7}{25}\]
you just use that with all of the functions? i have them written down. (: but how did you get 25?
\[\tan \theta=\frac{-24}{7}\]
I got 25 by using the Pythagorean Theorem
now the other functions are the reciprocals of those already given:
\[\cot \theta=\frac{1}{\tan \theta}=\frac{-7}{24}\]
\[\sec \theta=\frac{1}{\cos \theta}=\frac{-25}{7}\]
\[\csc \theta=\frac{1}{\sin \theta}=\frac{24}{25}\]
thank you ! i'm still a little confuzed about the 25. \[a ^{2}+b ^{2}=c ^{2}\] ? right?
yes
OH i'm sorry i get it now. i wasn't square rooting the final answer. thank you so much !
\[7^2+24^2=c^2=49+576=625\]
\[c^2=625\]
\[c=\sqrt{625}=25\]
thank you!

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