anonymous
  • anonymous
Charges q3 and q5 are now replaced by two charges, q2 and q6, having equal magnitude and sign (-3.4 μC). Charge q2 is located at the origin and charge q6 is located a distance d = d1 + d2 = 7.4 cm from the origin as shown. What is ΔPE, the change in potential energy now if charge q1 is moved from point P to point R? d2=2.1cm d1=5.3cm, q1=1.5microC
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
I believe this would equal zero because the q1 and q2 are equal on opposite sides and it
TuringTest
  • TuringTest
It would be nice to have a pic...
anonymous
  • anonymous
okay

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anonymous
  • anonymous
[url=http://postimage.org/image/ke883kxnr/][img]http://s15.postimage.org/ke883kxnr/Potential_energy_Problem.jpg[/img][/url]
anonymous
  • anonymous
There yeah go turmeister
anonymous
  • anonymous
unleash your wrath
anonymous
  • anonymous
zero
AravindG
  • AravindG
turing
AravindG
  • AravindG
cm there
TuringTest
  • TuringTest
yeah totally zero sorry, I was busy helping arvind
anonymous
  • anonymous
no prob dooooood/dudet

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