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anonymous

  • 4 years ago

Charges q3 and q5 are now replaced by two charges, q2 and q6, having equal magnitude and sign (-3.4 μC). Charge q2 is located at the origin and charge q6 is located a distance d = d1 + d2 = 7.4 cm from the origin as shown. What is ΔPE, the change in potential energy now if charge q1 is moved from point P to point R? d2=2.1cm d1=5.3cm, q1=1.5microC

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  1. anonymous
    • 4 years ago
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    I believe this would equal zero because the q1 and q2 are equal on opposite sides and it

  2. TuringTest
    • 4 years ago
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    It would be nice to have a pic...

  3. anonymous
    • 4 years ago
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    okay

  4. anonymous
    • 4 years ago
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    [url= http://postimage.org/image/ke883kxnr/ ][img] http://s15.postimage.org/ke883kxnr/Potential_energy_Problem.jpg [/img][/url]

  5. anonymous
    • 4 years ago
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    There yeah go turmeister

  6. anonymous
    • 4 years ago
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    unleash your wrath

  7. anonymous
    • 4 years ago
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    zero

  8. AravindG
    • 4 years ago
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    turing

  9. AravindG
    • 4 years ago
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    cm there

  10. TuringTest
    • 4 years ago
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    yeah totally zero sorry, I was busy helping arvind

  11. anonymous
    • 4 years ago
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    no prob dooooood/dudet

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spraguer (Moderator)
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