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anonymous

  • 4 years ago

Let f(t)=4 t^2 + 4/t^2. Find the slope of the curve at t = -3. Give both exact (symbolic) and approximate (numeric) answers.

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  1. anonymous
    • 4 years ago
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    df/dt=8t-2/t^2 so t=-3 => 8*(-3)-2/(-3)^2 -24-2/9 !

  2. anonymous
    • 4 years ago
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    so, just do the calculations and I have the answer?

  3. anonymous
    • 4 years ago
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    yup! ps: you know derivatives right?

  4. anonymous
    • 4 years ago
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    yeah, just use the power rule right?

  5. anonymous
    • 4 years ago
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    yes, derivatives is a simple way ;)

  6. anonymous
    • 4 years ago
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    but how do i use it in this problem?

  7. anonymous
    • 4 years ago
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    the derivatives is a function that describe the slope in every part of your main function, also in the -3 point ;)

  8. anonymous
    • 4 years ago
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    ok can you give me the equation? or formula?

  9. anonymous
    • 4 years ago
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    for calculate the derivatives?

  10. anonymous
    • 4 years ago
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    no, the equation to solve this problem

  11. anonymous
    • 4 years ago
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    I wrote it, df/dt is the derivatives of f(t) in t variables, maybe you like more f'(t)=8t-2/t^2 ?

  12. anonymous
    • 4 years ago
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    *more like

  13. anonymous
    • 4 years ago
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    I know you gave 8(-3) -2/-3^2 then -24-2/9

  14. anonymous
    • 4 years ago
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    but what do I do after that?

  15. anonymous
    • 4 years ago
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    ehm, sum XD I was lazy to sum the numbers, -218/9 is your slope

  16. anonymous
    • 4 years ago
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    i Dont know if that's right bcause when I plug that in to the system im on it's saying its wrong

  17. anonymous
    • 4 years ago
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    douch! maybe I've failed the derivatives!

  18. anonymous
    • 4 years ago
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    yup I failed, currect derivatives is: f'(t)=8t-8/t^3 sorry man

  19. anonymous
    • 4 years ago
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    hold on but the eqaution is f(t)=4 t^2 + 4/t^2.

  20. anonymous
    • 4 years ago
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    yes

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