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df/dt=8t-2/t^2 so t=-3 => 8*(-3)-2/(-3)^2 -24-2/9 !
so, just do the calculations and I have the answer?
yup! ps: you know derivatives right?
yeah, just use the power rule right?
yes, derivatives is a simple way ;)
but how do i use it in this problem?
the derivatives is a function that describe the slope in every part of your main function, also in the -3 point ;)
ok can you give me the equation? or formula?
for calculate the derivatives?
no, the equation to solve this problem
I wrote it, df/dt is the derivatives of f(t) in t variables, maybe you like more f'(t)=8t-2/t^2 ?
I know you gave 8(-3) -2/-3^2 then -24-2/9
but what do I do after that?
ehm, sum XD I was lazy to sum the numbers, -218/9 is your slope
i Dont know if that's right bcause when I plug that in to the system im on it's saying its wrong
douch! maybe I've failed the derivatives!
yup I failed, currect derivatives is: f'(t)=8t-8/t^3 sorry man
hold on but the eqaution is f(t)=4 t^2 + 4/t^2.