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A) standard equation of a parabola with vertex h and k y=a(x-h)^2+k here the vertex is -3,-2 so h=-3 and k=-2 hence \[y=a(x+3)^2-2\] here no information for a is given since the parabola is opening downeards, a is negative \[y=a(x+3)^2-2\]
here a is negative
okay let me look it over
do i put a in the y= equation?
yeah it's important
okay cool! thanks. How does B look
5 minutes, I'll take a look into it
sorry took long, dude I don't recognise this curve. Let me ask others for help
where did u go?
Hi, sorry kept you waiting I think this is tan x shifted y= 7+tan(x-14) as at x= 14 y=7
but I dnt think i would write it with tan in it
I've an idea let me work on it
thanks so much
just like the other on u showed me y=x^2, i think this type of graph is y=x^3
This is also a form of x^2 , it's vertex is (14,7) so y= (x-14)^2+7 for x>=14 and -(x-14)^2+7 for x<14
is that part the answer?
yeah for x>=14 we have a different function and for x<14 we have different
so it has that negative sign in front
welcome , do check them with your teacher and tell me if i got it right
butthe graph is positive
- sign is bringing the graph downward, it's initially positive, then it becomes negative . The negative part is not shown in the graph