Use shifts of power functions to find a possible formula for each of the graphs below. Assume the graphs are not being stretched. Attached are two pictures of A) graph and B) Graph

- anonymous

- schrodinger

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- anonymous

##### 1 Attachment

- anonymous

##### 1 Attachment

- ash2326

A)
standard equation of a parabola with vertex h and k
y=a(x-h)^2+k
here the vertex is -3,-2
so h=-3 and k=-2
hence
\[y=a(x+3)^2-2\]
here no information for a is given since the parabola is opening downeards, a is negative
\[y=a(x+3)^2-2\]

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## More answers

- ash2326

here a is negative

- anonymous

okay let me look it over

- anonymous

do i put a in the y= equation?

- ash2326

yeah it's important

- anonymous

okay cool! thanks. How does B look

- ash2326

5 minutes, I'll take a look into it

- anonymous

okay thanks

- ash2326

sorry took long, dude I don't recognise this curve. Let me ask others for help

- anonymous

thanks!

- ash2326

##### 1 Attachment

- anonymous

where did u go?

- ash2326

Hi, sorry kept you waiting
I think this is tan x shifted
y= 7+tan(x-14)
as at x= 14 y=7

- anonymous

but I dnt think i would write it with tan in it

- ash2326

I've an idea let me work on it

- anonymous

thanks so much

- anonymous

just like the other on u showed me y=x^2, i think this type of graph is y=x^3

- ash2326

This is also a form of x^2 , it's vertex is (14,7) so
y= (x-14)^2+7 for x>=14
and
-(x-14)^2+7 for x<14

- anonymous

is that part the answer?

- ash2326

yeah for x>=14 we have a different function and for x<14 we have different

- anonymous

so it has that negative sign in front

- ash2326

yeah

- anonymous

ok thanks

- ash2326

welcome , do check them with your teacher and tell me if i got it right

- anonymous

butthe graph is positive

- ash2326

- sign is bringing the graph downward, it's initially positive, then it becomes negative . The negative part is not shown in the graph

- anonymous

okay thanks

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