A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing


  • 4 years ago

make up an algebra problem involving two values which must be solved. then solve it, showing all steps and the solution.

  • This Question is Closed
  1. TuringTest
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    The classic: I have 4 coins in my hand, all quarters and dimes they total a value of 85cents how many of each coin do I have?

  2. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    The length of a rectangle is 7cm more than twice the width of the rectangle. If the perimeter of the rectangle is 38cm find the length and width of the rectangle. Let the length of the rectangle be x and width be y. Then x=2y+7 2x+2y=38--eqn1 x-2y=7--eqn2 eqn1+eqn2=>3x=45 x=15 2y=x-7 2y=15-7 =8 y=4 The length of the rectangle is 15cm and width of the rectangle is 4cm.

  3. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...


  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.