anonymous
  • anonymous
make up an algebra problem involving two values which must be solved. then solve it, showing all steps and the solution.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
TuringTest
  • TuringTest
The classic: I have 4 coins in my hand, all quarters and dimes they total a value of 85cents how many of each coin do I have?
anonymous
  • anonymous
The length of a rectangle is 7cm more than twice the width of the rectangle. If the perimeter of the rectangle is 38cm find the length and width of the rectangle. Let the length of the rectangle be x and width be y. Then x=2y+7 2x+2y=38--eqn1 x-2y=7--eqn2 eqn1+eqn2=>3x=45 x=15 2y=x-7 2y=15-7 =8 y=4 The length of the rectangle is 15cm and width of the rectangle is 4cm.

Looking for something else?

Not the answer you are looking for? Search for more explanations.