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anonymous

  • 4 years ago

How to find spring constant? m=0.05kg x = 10cm = 0.1m d = 2.7m hi = 1.5m m = 50g = 0.05kg g= 9.8m/s^2

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  1. anonymous
    • 4 years ago
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    The question basically looks like this. Sorry I couldn't draw the picture when I asked the question. |dw:1328552889143:dw|

  2. anonymous
    • 4 years ago
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    hehe thank you by the picture. Ep = 0,1 * F = Ec of the object.

  3. anonymous
    • 4 years ago
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    I will posting the steeps, if you got how you can do this exercise, tell me

  4. anonymous
    • 4 years ago
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    So, F = 0,1 * K ; Ec = V*V*0,05/2 ; V = 2,7/t

  5. anonymous
    • 4 years ago
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    5 = (9,8/2) * t*t ; So you got t = 2,2 s ; Then V = 2,7/t => 2,7/2,2 => V = 1,23 Then Ec = \[((1,23)^{2} * 0,05)/2\] => 0,04 J = Ep (Ep = potential energy of the spring ) Ep = 0,04 J = 0,1 * F F = 0,4 N In fact : \[F = \Delta d*K \] and \[\Delta d = 0,1 \] So 0,4 = 0,1 * K K = 4 ! I think that is right, cya !

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